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Question

The value of (1+12)(1+13)(1+14)×..×(1+12019) is
  1. 2019  
  2. 2020 
  3. 1010  
  4. 1009


Solution

The correct option is C 1010  
(1+12)(1+13)(1+14)×..×(1+12019)
=32×43×54×...×20202019=20202=1010

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