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Question

The value of ((log29)2)1log2(log29)×(7)1log47 is

A
5
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B
6
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C
7
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D
8
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Solution

The correct option is D 8
((log29)2)1log2(log29)×(7)1log47=((log29))2log2(log29)×712log47

Assuming log29=a
=a2log2a×7log742=a2loga2×7log72=4×2=8

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