Question

The value of Bohr Magneton is given by :

• A. $eh/4\pi m$
• B. $eh/4\pi mc$
• C. $e/4\pi m$
• D. $e^{2}h/2\pi mc$

Answer 1

Answer: (A)

$eh/4\pi m$

Short comings of Bohr's atomic model are

1) Bohr treated electrons as

there fore exhibits wave nature

2). Bohr's model was adequate only for nucleus only one electron but Bohr Spectra of multi - electronic at mas

3) Bohr's model was two dimensional three dimensional

The value of Bohr Magneton is given by eh $/4\pi m$

To verily this we can but the ves $e=1.6\times {10}^{-19}c$

$h=6.64\times {10}^{-34}{J}_5$

$m=9.1\times {10}^{-31}kg$

$\therefore {\mu }_B=\frac{1.60\times {10}^{-19}\times 6.64\times {10}^{-34}}{4\times \pi \times 9.1\times {10}^{-31}}$

${\mu }_B=9.27\times {10}^{-24}{Am}^2$

Hence proved.

$\left[A\right)=eh/4\pi m$