The value of c, for which the function f(x)=x2+2x–8,xϵ[–4,2] satisfies Rolle’s theorem, is
1
2
-1
-2
f’(x) = 0 ⇒ 2x + 2 = 0 ⇒ x = – 1
∴c=–1
Verify Rolle's theorem for the function f(x)=x2+2x−8,xϵ[−4,2]