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Circle

The value of ...

Question

The value of $c$ , for which the line $y = 2 x + c$ is a tangent to the circle $x^{2} + y^{2} = 16$ , is

- 16 \sqrt{5}

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20

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4 \sqrt{5}

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16 \sqrt{5}

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Solution

The correct option is B $4 \sqrt{5}$
$x^{2} + y^{2} = 16 & y = 2 x + C$

$2 x - y + C = 0$

$\frac{| C |}{\sqrt{5}} = 4$

$C = \pm 4 \sqrt{5}$

$H e n c e, t h e o p t i o n C i s t h e c o r r e c t a n s w e r .$

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Similar questions

c

y = 2 x + c

x^{2} + y^{2} = 5

y = 2 x + c

x^{2} + y^{2} = 16

y = 2 x + c

x^{2} + y^{2} = 5

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x + 4 y - 5 = 0

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