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Question

The value of c in the lagranges mean value theorem for f(x)=x3,a=1,h=12 is

A
13
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B
1956
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C
193+2
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D
1932
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Solution

The correct option is D 1932
f(x) is continous & differentiable
f(x)=3x2
f(c)=f(32)f(1)12
3c2=278112
3c2=194

c=12193

c ϵ (1,32)

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