Question

The value of c in the Roll’s theorem for the function $f\left(x\right)=x^3–3x$ in the interval $[0,\sqrt{3}]$ is

• A. 1
• B. -1
• C. 3/2
• D. 1/3

Answer 1

The correct option is A

1

$f^{\prime }\left(c\right)=0\Rightarrow 3c^2–3=0$

$\Rightarrow c=1$