The value of Cp−Cv is 1.09R for a gas sample in state A and is 1.00R in state B. Let TA,TB denote the temperature and PA and PB denote the pressure of the states A and B respectively. Then:
A
PA<PB and TA>TB
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B
PA>PB and TA>TB
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C
PA=PB and TA=TB
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D
PA>PB and TA<TB
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Solution
The correct option is APA<PB and TA>TB For state A, CP−CV=R i.e. the gas behaves as ideal gas.
For state B, CP−CV=1.06R(≠R) i.e. the gas does not behave like ideal gas and we know that at high temperature & at low pressure the nature of gas may be ideal.