The value of C $_{v}$ for 1 mol of polyatomic gas is (F $=$ number of degrees of freedom) :

\frac{f R}{2 T}

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\frac{f R}{2}

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\frac{f R T}{2}

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2 f R T

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Solution

The correct option is A $\frac{f R}{2}$
The value of C $_{v}$ for 1 mol of polyatomic gas is $\frac{f R}{2}$
where f is no of degrees of freedom (in a gas for every degree of freedom we have energy distribution as $\frac{k T}{2}$ )

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