The value of $C_{v}$ for one mole of neon gas is

$\frac{1}{2} R$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{3}{2} R$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{5}{2} R$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{7}{2} R$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
$\frac{3}{2} R$

Neon is a monoatomic gas. $C_{v} = \frac{3 R}{2}$

Suggest Corrections

Similar questions

The value of $C_{v}$ for one mole of neon gas is

For two moles of gas proove Cp - Cv = R

\frac{C_{p}}{C_{v}} = 5 / 3

\frac{C_{p}}{C_{v}} = 4 / 3

\frac{C_{p}}{C_{v}}

2

C_{p}

C_{v}

Join BYJU'S Learning Program