The value of $C_{v}$ for one mole of neon gas is

$\frac{1}{2} R$

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$\frac{3}{2} R$

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$\frac{5}{2} R$

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$\frac{7}{2} R$

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Solution

The correct option is B
$\frac{3}{2} R$

Neon is a monoatomic gas. $C_{v} = \frac{3 R}{2}$

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Similar questions

The value of $C_{v}$ for one mole of neon gas is

For two moles of gas proove Cp - Cv = R

\frac{C_{p}}{C_{v}} = 5 / 3

\frac{C_{p}}{C_{v}} = 4 / 3

\frac{C_{p}}{C_{v}}

2

C_{p}

C_{v}

β

β = \frac{C_{p}}{C_{v}}

β

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