Question

The value of $\frac{{18}^3+7^3+\mathrm{3.18.7.25}}{3^6+\mathrm{6.243.2}+\mathrm{15.81.4}+\mathrm{20.27.8}+\mathrm{15.9.16}+\mathrm{6.3.}{3}^2+64}$ is equal to:

• A. $1000$
• B. $1/1000$
• C. $1$
• D. $1/2000$

Answer 1

The correct option is C $1$

$\frac{{18}^3+7^3+\mathrm{3.18.7.25}}{3^6+\mathrm{6.243.2}+\mathrm{15.81.4}+\mathrm{20.27.8}+\mathrm{15.9.16}+\mathrm{6.3.}32+64}=\frac{{18}^3+7^3+\mathrm{3.18.7.}(18+7)}{3^6+6{.3}^5.2+\mathrm{5.3.}{3}^4.2^2+\mathrm{5.4.}{3}^3.2^3+5.3{.3}^2.2^4+\mathrm{6.3.}{2}^5+2^6}=\frac{{(18+7)}^3}{{(3+2)}^6}=\frac{{25}^3}{5^6}=\frac{5^6}{5^6}=1$

Answer $C$