The value of $c o s^{- 1} (c o s 12) - s i n^{- 1} (s i n 12)$ is:

0.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

π

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 π - 24

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8 π - 24$
$\frac{7 π}{2} < 12 < 4 π$
$∴ c o s^{- 1} 12 = 4 π - 12$ and $s i n^{- 1} 12 = 12 - 4 π$ .
$∴ c o s^{- 1} 12 - s i n^{- 1} 12 = (4 π - 12) - (12 - 4 π) = 8 π - 24$

Suggest Corrections

Similar questions

{sin}^{- 1} (sin 12) - {cos}^{- 1} (cos 12) =

{s i n}^{- 1} (s i n 12) + {c o s}^{- 1} (c o s 12)

(k - 2) x^{2} + 8 x + k + 4 > {sin}^{- 1} (sin 12) + {cos}^{- 1} (cos 12)

x ϵ R

k

(k - 2) x^{2} + 8 x + k + 4 > {sin}^{- 1} (sin 12) + {cos}^{- 1} (cos 12)

x \in R

The least value of n for which $(n - 2)^{2} + 8 x + n + 4 > s i n^{- 1} (s i n 12) + c o s^{- 1} (c o s 12) \forall x ϵ R$ and $n ϵ N$ is

Join BYJU'S Learning Program