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Question

The value of cos12o+cos84o+cos156o+cos132o is

A
12
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B
1
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C
12
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D
18
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Solution

The correct option is C 12
cos12+cos84+cos156+cos132=(cos132+cos12)+(cos84+cos156)
=2cos(132122)cos(132+122)+2cos(84+1562)cos(156842)
=2cos60cos72+2cos120cos36
=2×12×514+2×(12)×5+14
=5145+14
=12

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