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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Allied Angles
The value of ...
Question
The value of
cos
12
o
+
cos
84
o
+
cos
156
o
+
cos
132
o
is
A
1
2
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B
1
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C
−
1
2
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D
1
8
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Solution
The correct option is
C
−
1
2
cos
12
∘
+
cos
84
∘
+
cos
156
∘
+
cos
132
∘
=
(
cos
132
∘
+
cos
12
∘
)
+
(
cos
84
∘
+
cos
156
∘
)
=
2
cos
(
132
∘
−
12
∘
2
)
cos
(
132
∘
+
12
∘
2
)
+
2
cos
(
84
∘
+
156
∘
2
)
cos
(
156
∘
−
84
∘
2
)
=
2
cos
60
∘
cos
72
∘
+
2
cos
120
∘
cos
36
∘
=
2
×
1
2
×
√
5
−
1
4
+
2
×
(
−
1
2
)
×
√
5
+
1
4
=
√
5
−
1
4
−
√
5
+
1
4
=
−
1
2
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Q.
Solve:
cos
12
o
+
cos
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o
+
cos
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o
+
cos
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o
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up to 4 places of decimal is
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W
−
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(1)
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(2)
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