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Question

The value of cos2A+cos2B2cosAcosBcos(A+B)sin2(A+B)

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Solution

L.H.S. = cos2A+cos2B2cosAcosB(cosAcosBsinAsinB)
=(cos2Acos2Acos2B)+(cos2Bcos2Acos2B)+2sinAsinBcosAcosB
=cos2A(1cos2B)+cos2B(1cos2A)+2sinAsinBcosAcosB
=cos2Asin2B+cos2Bsin2A+2sinAsinBcosAcosB
=(sinAcosB+cosAsinB)2=sin2(A+B)

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