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Question

The value of cos2(π8+x)sin2(3π8x) is

A
1
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B
0
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C
1
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D
2
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Solution

The correct option is B 0
We know that,
cos2Asin2B=cos(A+B)cos(AB)cos2(π8+x)sin2(3π8x)=cos(π2)cos(2xπ4)=0

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