The value of cos $25^{0} cos 20^{0} + sin 25^{0} sin 20^{0}$ is

\frac{1}{\sqrt{2}}

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2

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cos 5^{0}

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sin 5^{0}

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Solution

The correct option is D $cos 5^{0}$
$cos 25^{0} . cos 20^{0} + sin 25^{0} . sin 20^{0}$
$= cos (25^{0} - 20^{0}) = cos 5^{0}$

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The value of cos 250cos200+sin250sin200 is

The correct option is D cos50cos250.cos200+sin250.sin200=cos(250−200)=cos50

The value of cos $25^{0} cos 20^{0} + sin 25^{0} sin 20^{0}$ is

The correct option is D $cos 5^{0}$
$cos 25^{0} . cos 20^{0} + sin 25^{0} . sin 20^{0}$
$= cos (25^{0} - 20^{0}) = cos 5^{0}$