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Question

The value of cos(2π7)+cos(4π7)+cos(6π7)=-1a. Find a.


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Solution

Determine the value of a in cos(2π7)+cos(4π7)+cos(6π7)=-1a.

cos(2π7)+cos(4π7)+cos(6π7)=-1a2cos3π7cosπ7+cos6π7=-1a2cos3π7cosπ7-cosπ7=-1acosπ72cos3π7-1=-1acosπ72cos3π7-1sin3π7sin3π7=-1acosπ72cos3π7cos3π7-sin3π7sin3π7=-1acosπ7sin6π7-sin3π7sin3π7=-1acosπ72sin3π14cos9π142sin3π14cos3π14=-1acosπ7cos9π14cos3π14=-1a12cos11π14+cos7π14cos3π14=-1a12-cos3π14+0cos3π14=-1a-12=-1aa=2

Hence, the value of a is 2.


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