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Question

The value of cos4+θ+sin4θ6 cos2θ sin2θ is


A

cos 2θ

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B

sin 2θ

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C

cos 4θ

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D

none of these

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Solution

The correct option is C

cos 4θ


cos4 θ+sin4θ6 cos2θ sin2θ=cos4θ+sin4θ2 cos2θ sin2 θ4 cos2θ sin2θ=(cos2θsin2θ)(2 sinθ cos θ)2=cos2 2θsin2 2θ=cos 4θ


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