Question

The value of cos{ $co{s}^{-1}\left(\frac{\sqrt{3}}{2}\right)+\frac{\pi }{6}$} is

• A. $1$
• B. $-1$
• C. $0$
• D. $\frac{1}{2}$

Answer 1

The correct option is D $\frac{1}{2}$

$\cos ({\text{cos}}^{-1}(\frac{\sqrt{3}}{2})+\frac{\pi }{6})=\cos (\frac{\pi }{6}+\frac{\pi }{6})$

$=\cos \frac{2\pi }{6}$

$=\cos \frac{\pi }{3}$

$=\frac{1}{2}$