The value of cos2-7cos4-7cos6-7 is

The correct option is D 18 Take α = π7 , the 7 α = π, 6 α = π α cos2α . cos4α . cos6α = cos2α . cos4α . cos (π α) = cosα . cos2α ...

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The value of $cos \frac{2 π}{7} cos \frac{4 π}{7} cos \frac{6 π}{7}$ is

- \frac{1}{2}

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\frac{1}{2}

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\frac{1}{4}

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\frac{1}{8}

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cos \frac{2 π}{7} + cos \frac{4 π}{7} + cos \frac{6 π}{7} = - \frac{1}{2}

cos \frac{2 π}{7} cos \frac{4 π}{7} cos \frac{6 π}{7} = \frac{1}{8}

{c o s e c}^{2} \frac{π}{7} + {c o s e c}^{2} \frac{2 π}{7} + {c o s e c}^{2} \frac{3 π}{7}

c o s \frac{2 π}{7} c o s \frac{4 π}{7} c o s \frac{6 π}{7} = \frac{1}{8}

c o s \frac{π}{11} c o s \frac{2 π}{11} c o s \frac{3 π}{11} c o s \frac{4 π}{11} c o s \frac{5 π}{11} = \frac{1}{32}

cos \frac{π}{7} cos \frac{2 π}{7} cos \frac{4 π}{7} = - \frac{1}{8}

\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}}

\frac{1}{\sqrt{9} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{1}}

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