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Trigonometric Ratios of Multiples of an Angle

The value of ...

Question

The value of $cos (\frac{3 π}{2} + θ) cos (2 π + θ) [cot (\frac{3 π}{2} - θ) + cot (2 π + θ)]$ is

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Solution

$cos (\frac{3 π}{2} + θ) cos (2 π + θ) [cot (\frac{3 π}{2} - θ) + cot (2 π + θ)] = sin θ cos θ [tan θ + cot θ] = sin θ cos θ [\frac{sin θ}{cos θ} + \frac{cos θ}{sin θ}] = sin θ cos θ [\frac{{sin}^{2} θ + {cos}^{2} θ}{cos θ sin θ}] = 1$

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cos (\frac{3 π}{2} + θ) cos (2 π + θ) [cot (\frac{3 π}{2} - θ) + cot (2 π + θ)] = 1

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, then find the value of

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then find the value of

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sin (π - θ) + cos (\frac{3 π}{2} + θ) + sin (π + θ) + cos (\frac{3 π}{2} - θ) = ?

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Trigonometric Ratios of Multiples of an Angle

Standard XII Mathematics

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