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B
sin(−π5)
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C
cos(2π5)
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D
−cos(3π5)
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Solution
The correct option is Ccos(2π5) Let be very careful about the interval in which the angle belongs to. θ=−14π5=−2.8π ∴−3π < θ < −2π i.e.,[2(-1)-1] π < θ < −2π. ∴cos−1(cosθ)=2(−1)π−θ=−2π−θ=−2π+14π5=4π5∴cos(12cos−1.cos(−14π5))=cos(12.4π5)=cos(2π5)