The value of cos-cos90-sin-sin90- is-

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Standard X

Mathematics

Value of Standard Angle(30,60,90)

The value of ...

Question

The value of cos θ cos(90^o - θ) - sin θ sin (90^o - θ) is:

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Solution

The correct option is B
0

cos θ cos(90^o - θ) - sin θ sin (90^o - θ )

= cos θ sin θ - sin θ cos θ

= 0

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Similar questions

Prove the following:

(i) $s i n θ s i n (90^{o} - θ) - c o s θ c o s (90^{o} - θ) = 0$
(ii) $\frac{c o s (90^{o} - θ) s e c (90^{o} - θ) t a n θ}{c o s e c (90^{o}) s i n (90^{o} - θ) c o t (90^{o} - θ)} + \frac{t a n (90^{o} - θ)}{c o t θ} = 2$
(iii) $\frac{t a n (90^{o} - A) c o t A}{c o s e c^{2} A} - c o s^{2} A = 0$
(iv) $\frac{c o s (90^{o} - A) s i n (90^{o} - A)}{t a n (90^{o} - A)} = s i n^{2} A$
(v) $s i n (50^{o} + θ) - c o s (40^{o} - θ) + t a n 1^{o} t a n 10^{o} t a n 20^{o} t a n 70^{o} t a n 80^{o} t a n 89^{o} = 1$

Q. The value of

\frac{cos Θ}{sin (90 + Θ)} + \frac{sin (- Θ)}{sin (180 + Θ)} + \frac{tan (90 + Θ)}{cot Θ}

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csc (65^{0} + θ) - sec (25^{0} - θ) - tan (55^{0} - θ) + cot (35^{0} + θ)

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2 ({sin}^{6} θ + {cos}^{6} θ) - 3 ({sin}^{4} θ + {cos}^{4} θ) + 1

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The value of cos θ cos(90o - θ) - sin θ sin (90o - θ) is:

The correct option is B 0cos θ cos(90o - θ) - sin θ sin (90o - θ ) = cos θ sin θ - sin θ cos θ = 0

The value of cos θ cos(90^o - θ) - sin θ sin (90^o - θ) is:

The correct option is B
0

cos θ cos(90^o - θ) - sin θ sin (90^o - θ )

= cos θ sin θ - sin θ cos θ

= 0