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Question

The value of (cos2 23° – sin2 67°) is ____________.

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Solution


We know that,
cos23°=cos90°-67°=sin67° cos90°-θ=sinθ
cos223°-sin267°=sin267°-sin267°=0

The value of (cos2 23° – sin2 67°) is ______0______.

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