CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of cos69°45' - cos15°40' is .

A
0.6168
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.6168
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.6618
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.6618
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.6168
We can write,
69°45' = 69°42' + 3'
From the table we have, cos69°42' = 0.3469
Mean difference for 3′ = 8 (Mean difference to be subtracted for cosine)
cos69°42' = 0.3469
3′ = - 8
____________________
cos69°45' = 0.3461 ... (i)


We can write,
15°40' = 15°36' + 4'
From the table we have, cos15°36' = 0.9632
Mean difference for 4′ = 3 (Mean difference to be subtracted for cosine)
cos15°36' = 0.9632
4′ = - 3
____________________
cos15°40' = 0.9629 ... (ii)

From equations (i) and (ii), we get
cos69°45' - cos15°40' = 0.3461 - 0.9629 = - 0.6168

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Ratios of Complementary Angles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon