The value of cosx in the second quadrant

increases from 0 to 1

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increases from -1 to 0

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decreases from 1 to 0

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decreases from 0 to -1

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Solution

The correct option is D
decreases from 0 to -1

The value of cos function at 90 degrees is 0 and at 180 degrees it’s -1.Thus as the angle moves from 90 degrees to 180 degrees i.e. in the second quadrant , the value decreases from 0 to -1.

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Similar questions

What is the value of cos x in second quadrant if sin x = 3/5 in II quadrant

cos x = - \frac{1}{3}

sin \frac{x}{2}, cos \frac{x}{2}, tan \frac{x}{2}

\sin x = \frac{2 t}{1 + t^{2}}

\cos x = - \frac{3}{5}

\cos \frac{x}{2}, \sin \frac{x}{2}, \sin 2 x

\cos x = - \frac{3}{5}

\sin \frac{x}{2}

Prove that:

(i) If $c o s x = - \frac{3}{5}$ and x lies in the IIIrd quadrant, find the values of $c o s \frac{x}{2}, s i n \frac{x}{2}$ and sin 2x.

(ii) If $c o s x = - \frac{3}{5}$ and x lies in the IInd quadrant, find the values of sin 2x and sin $\frac{x}{2}$

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