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Question

The value of cot2π12tan2π12 is

A
43
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B
83
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C
23
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D
83
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Solution

The correct option is B 83
Let x=π12
cot2π12tan2π12=cot2xtan2x=(cotx+tanx)(cotxtanx)=(1sinxcosx)×(cos2xsinxcosx)(cos2xsin2x=cos2x)=4cos2xsin22x=4cosπ6sin2π6=4×2×3=83

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