Question

The value of $\cot \left({660}^o\right)+\tan (-{1050}^o)$.

• A. $0$
• B. $-\frac{2}{\sqrt{3}}$
• C. $2\sqrt{3}$
• D. None of these

Answer 1

The correct option is A $0$

Now,

$\cot \left({660}^o\right)+\tan (-{1050}^o)$

$=\cot (7\times {90}^o+{30}^o)-\tan (12\times {90}^o-{30}^o)$ [ Since $\tan (-x)=-\tan x$]

$=-\tan {30}^o+\tan {30}^o$

$=0$.