The value of -4-4- is

The correct option is B 1 ⟶(π4 θ).(π4+θ) =1tan(π4 θ)×1tan(π4+θ) =1+tanθ1 tanθ×(1 tanθ1+tanθ) =1 ...

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Sin(A+B)Sin(A-B)

The value of ...

Question

The value of $cot (\frac{π}{4} + θ) . cot (\frac{π}{4} - θ)$ is

1

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\frac{cot (\frac{π}{2} + θ) . sin (- θ) . (cot π - θ)}{cos (2 π - θ) . sin (π + θ) . tan (2 π - θ)} = - csc θ

θ

\frac{π}{4}

\frac{5 π}{4}

4 cos \frac{1}{2} θ

θ \in (\frac{π}{4}, \frac{π}{2})

\infty \sum n = 1 \frac{1}{{tan}^{n} θ} = sin θ + cos θ

tan θ

θ

θ = 0

\frac{π}{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + {sin}^{2} θ & {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & 1 + {cos}^{2} θ & 4 sin 4 θ {sin}^{2} θ & {cos}^{2} θ & 1 + 4 sin 4 θ \end{matrix} ∣ ∣ ∣ ∣ ∣ = 0

\frac{π}{2} < θ < \frac{3 π}{2}

= \sqrt{4 {cos}^{4} θ + {sin}^{2} 2 θ} + 4 cot θ {cos}^{2} (\frac{π}{4} - \frac{θ}{2})

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