The value of cot θ in the given right triangle is
√2
1
1√2
12
In the given triangle,
BC2=AC2−AB2 (By Pythagoras theorem)
⇒BC2=2−1=1
cotθ=Adjacentsideoppositeside
cotθ=ABBC=1
What is the value of cot θ in the given right triangle?
The value of sec θ in the given triangle is,
Find the value of θ, in the right triangle △ ABC.