Question

The value of current I and voltage V in the given circuit will be _____________.

• A. 2 A, 4 V
• B. 4 A, 2 V
• C. 1 A,2 V
• D. 2 A, 1 V

Answer 1

The correct option is A 2 A, 4 V

$R_{eq.}=\frac{R_1{R}_2}{R_1+R_2}=\frac{6\times (2+2+2)}{6+(2+2+2)}=\frac{36}{12}=3\Omega$
$I_{total}=\frac{V}{R_{eq}}=\frac{12}{3}=4Amp.$
$I=\frac{I_{total}}{2}=\frac{4}{2}=2Amp.$
Voltage drop across $2\Omega$ resister is $V=IR=2\times 2=4Volt$