The value of current in other resistances in the adjoining circuit diagram will be

0.1A

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0.5A

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0.05A

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0.01A

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Solution

The correct option is C 0.05A
current in other resistances in the adjoining circuit diagram will be = $\frac{3}{10 + 20 + 30} = \frac{3}{60} = 0.05 A$

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