The value of current in the 60- resistance in the adjoining circuit diagram will be

The correct option is B 0.05AAs per the diagram the voltage across 60 Ω resistor is 3V. #160;Therefore the current through the resistor will be I = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Zener Diode as Voltage Stabilizer

The value of ...

Question

The value of current in the $60 Ω$ resistance in the adjoining circuit diagram will be

0.1A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.05A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.01A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 0.05A
As per the diagram the voltage across $60 Ω$ resistor is 3V.
Therefore the current through the resistor will be
$I = \frac{V}{R}$

$I = \frac{3}{60} = 0.05 A$

Suggest Corrections

Similar questions

Q. The value of current in other resistances in the adjoining circuit diagram will be

Q. In the adjoining circuit diagram each resistance is of

10 Ω

. The current in the arm AD will be

Q. In the adjoining circuit diagram each resistance is of 10

Ω

. The current in the arm AD will be

Q. The equivalent resistance between point

A

and

B

in the line adjoining circuit diagram will be:

Q. In the circuit diagram given below five resistances of 10 Ω, 40 Ω, 30 Ω, 20 Ω, and 60 Ω are connected as shown to a 12 V battery.

Calculate:
(a) total resistance in the circuit.
(b) total current flowing in the circuit.

Join BYJU'S Learning Program

The value of current in the 60Ω resistance in the adjoining circuit diagram will be

The correct option is B 0.05AAs per the diagram the voltage across 60Ω resistor is 3V. Therefore the current through the resistor will beI=VRI=360=0.05A

The value of current in the $60 Ω$ resistance in the adjoining circuit diagram will be

The correct option is B 0.05A
As per the diagram the voltage across $60 Ω$ resistor is 3V.
Therefore the current through the resistor will be
$I = \frac{V}{R}$

$I = \frac{3}{60} = 0.05 A$