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Question
The value of Δ=∣∣
∣∣0sinα−cosα−sinα0sinβcosα−sinβ0∣∣
∣∣ is
The value of Δ=∣∣
∣∣0sinα−cosα−sinα0sinβcosα−sinβ0∣∣
∣∣ is
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Solution
The correct option is A 0
Expanding along R1, we get
Δ=0∣∣∣0sinβ−sinβ0∣∣∣−sinα∣∣∣−sinαsinβcosα0∣∣∣−cosα∣∣∣−sinα0cosα−sinβ∣∣∣
=0−sin α(0−sin β cos α)−cos α(sin α sin β−0)
=sin α sin β cosα−cos α sin α sin β=0
Expanding along R1, we get
Δ=0∣∣∣0sinβ−sinβ0∣∣∣−sinα∣∣∣−sinαsinβcosα0∣∣∣−cosα∣∣∣−sinα0cosα−sinβ∣∣∣
=0−sin α(0−sin β cos α)−cos α(sin α sin β−0)
=sin α sin β cosα−cos α sin α sin β=0
Suggest Corrections
0
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