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Byju's Answer
Standard XII
Mathematics
Sarrus Rule
The value of ...
Question
The value of
Δ
=
∣
∣ ∣
∣
1
2
4
−
1
3
0
4
1
0
∣
∣ ∣
∣
is
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Solution
Note that in the third column,two entries are zero, So expanding along third column
(
C
3
,
)
we get
Δ
=
4
∣
∣
∣
−
1
3
4
1
∣
∣
∣
−
0
∣
∣
∣
1
2
4
1
∣
∣
∣
+
0
∣
∣
∣
1
2
−
1
3
∣
∣
∣
=
4
(
−
1
−
12
)
−
0
+
0
=
−
52
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0
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Sarrus Rule
Standard XII Mathematics
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