Question

The value of $\Delta G^o$ for the phosphorylation of glucose in glycolysis is $13.8kJ/mol$. Find the value of $K_c$ at $298$K.

Answer 1

$\Delta G^o=13.8kJ/mol=13.8\times {10}^{3}J/mol$
Also, $\Delta G^o=-RTIn{K}_c$
Hence, $In{K}_c=-13.8\times {10}^{3}J/mol$
$(8.314Jmo{l}^{-1}{K}^{-1}\times 298K)$
$In{K}_c=-5.569$
$K_c=e^{-5.569}$
$K_c=3.81\times {10}^{-3}$