The value of - H - U for the following reaction at 27- will be - 2 NH 3 g - N 2 g -3 H 2 g A- 8-314 - 273 -2 JB- -800 RC- 8-314 - 300 -2 JD- 8-314 - 300 - 2 J

The correct option is C 8.314 ×300×( 2) J 2NH_3 ⇋ N_2 +3H_2 (g) (g) (g) Δ H = Δ U + Δ nRT Δ n =4 2 =(2) Δ H = Δ U = Δ nRT ...

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Standard XII

Chemistry

Internal Energy

The value of ...

Question

The value of $Δ H - Δ U$ for the following reaction at $27^{\circ}$ will be : $2 N H_{3 (g)} \to N_{2 (g)} + 3 H_{2 (g)}$

8.314 ×273 ×( -2) J

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8.314 ×300×( -2) J

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- 800R

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8.314×300×2 J

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Solution

The correct option is B
8.314 ×300×( -2) J

$2 N H_{3} ⇋ N_{2} + 3 H_{2} (g) (g) (g) Δ H = Δ U + Δ n R T Δ n = 4 - 2 = (2) Δ H = Δ U = Δ n R T = - 2 \times 8.314 \times 300 J R = 2 c a l, R = 8.3145$

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Q. The value of

Δ H - Δ U

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C will be:

2 N H_{3} (g) \to N_{2} (g) + 3 H_{2} (g)

Rate of disappearance of the reactant A in the reversable and one step reaction $A ⇌ B$ at two temperatures is given by
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