The value of ΔHO−H is 109kcalmol−1. The formation of one mole of water in gaseous state from H(g) and O(g) is accompanied by:
A
218kcal
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B
−109kcal
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C
−218kcal
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D
Unpredictable
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Solution
The correct option is C−218kcal The involved reaction is, 2H(g)+O(g)→H2O(g) => ΔH=−2×ΔHO−H Hence, formation of one mole of water in gaseous state from H(g) and O(g) is accompained by, ΔH=−2×109=−218Kcal Hence, the answer is option C.