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Question

The value of ΔHsol. of BaCl2(s) and BaCl2.2H2O(s) are - a kJ and b kJ respectively. The value of ΔHHydration of BaCl2(s) is:

A
b - a
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B
a + b
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C
- a - b
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D
a - b
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Solution

The correct option is D - a - b
Solution:- (C) ab
BaCl2(s)+aq.BaCl2aq.ΔH=akJ.....(1)
BaCl2.2H2O(s)+aq.BaCl2(aq.)+2H2OΔH=bkJ
BaCl2(aq.)+2H2OBaCl2.2H2O(s)+aq.ΔH=bkJ.....(2)
Adding eqn(1)&(2), we have
BaCl2(s)+aq.+BaCl2(aq.)+2H2O(l)BaCl2aq.+BaCl2.2H2O(s)+aq.ΔH=(a)+(b)
BaCl2(s)+2H2O(l)BaCl2.2H2OΔH=abkJ
Hence the heat of hydration of anhydrous BaCl2 is abkJ.

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