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Question

The value of determinant ∣ ∣abb+cabcc+abcaa+bc∣ ∣ is

A
a3+b3+c3
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B
3abc
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C
a3+b3+c33abc
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D
a3+b3+c3+3abc
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Solution

The correct option is C a3+b3+c33abc
=∣ ∣abb+cabcc+abcaa+bc∣ ∣

Applying R1R1+R2+R3, we get
=(a+b+c)∣ ∣021bcc+abcaa+bc∣ ∣

Expanding along R1, we get
=(a+b+c)[2c(bc)+2b(ca)+(bc)(a+b)(ca)(c+a)]
=(a+b+c)(a2+b2+c2abbcac)
=a3+b3+c33abc

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