The value of determinant ∣∣
∣∣x+1x+2x+4x+3x+5x+8x+7x+10x+14∣∣
∣∣ is?
A
−2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x2+2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A−2 Operating C3−C2 and C2−C1, we get Δ=∣∣
∣∣x+112x+323x+734∣∣
∣∣ Apply R3−R2,R2−R1 Δ=∣∣
∣∣x+112211411∣∣
∣∣ apply C3−C2 ∣∣
∣∣x+111210410∣∣
∣∣=1.(2−4)=−2