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Question

The value of determinant ∣ ∣x+1x+2x+4x+3x+5x+8x+7x+10x+14∣ ∣ is?

A
2
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B
x2+2
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C
2
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D
None of these
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Solution

The correct option is A 2
Operating C3C2 and C2C1, we get Δ=∣ ∣x+112x+323x+734∣ ∣
Apply R3R2,R2R1
Δ=∣ ∣x+112211411∣ ∣ apply C3C2
∣ ∣x+111210410∣ ∣=1.(24)=2

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