The value of determinant Δ=∣∣
∣
∣∣x−x2−x3−x2x2−x−x3−xx3∣∣
∣
∣∣,(Δ≠0,x≠0) is equal to
A
−x3[1+x+x2+x3+x4+x5]
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B
−x3[1+x2+x3+x4+x5]
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C
−x3[1+x3+x4+x5]
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D
−x3[1+x+x2+x3+x4]
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Solution
The correct option is C−x3[1+x3+x4+x5] Given : Δ=∣∣
∣
∣∣x−x2−x3−x2x2−x−x3−xx3∣∣
∣
∣∣
Put x=1 in the above determinant, ⇒Δ=∣∣
∣∣1−1−1−11−1−1−11∣∣
∣∣ =1(1−1)+1(−1−1)−1(1+1)=−4
Putting x=1, in the given options ∴ Only one option satisfies above result i.e. −x3[1+x3+x4+x5]