Question

The value of determinant $△=\left|\begin{array}{ccc}-2& 3& 10\\ 3& -4& -1\\ 8& -12& -40\end{array}\right|$ is equal to

• A. $2$
• B. $-1$
• C. $1$
• D. $0$

Answer 1

The correct option is D $0$

Given : $△=\left|\begin{array}{ccc}-2& 3& 10\\ 3& -4& -1\\ 8& -12& -40\end{array}\right|$
Now taking $-4$ common from $R_3,$
$\Rightarrow △=-4\left|\begin{array}{ccc}-2& 3& 10\\ 3& -4& -1\\ -2& 3& 10\end{array}\right|=0$
($\because R_1$ and $R_3$ are same)