The value of determinant using sarrus method ∣∣
∣∣−12−33−2121−3∣∣
∣∣ is
A
4
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B
−4
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C
18
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D
−18
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Solution
The correct option is B−4 Using 'Sarrus' method : ∣∣
∣∣a1b1c1a2b2c2a3b3c3∣∣
∣∣=[a1b2c3+b1c2a3+c1a2b3]−[a3b2c1+b3c2a1+c3a2b1]=[−6+4+(−9)]−[(−18)+(−1)+12]=−4