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Question

The value of determinant using sarrus method ∣∣ ∣∣−12−33−2121−3∣∣ ∣∣ is

A
4
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B
4
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C
18
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D
18
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Solution

The correct option is B 4
Using 'Sarrus' method : ∣ ∣a1b1c1a2b2c2a3b3c3∣ ∣=[a1b2c3+b1c2a3+c1a2b3][a3b2c1+b3c2a1+c3a2b1]=[6+4+(9)][(18)+(1)+12]=4

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