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Nernst Equation

The value of ...

Question

The value of determinant using sarrus method $∣ ∣ ∣ ∣ \begin{matrix} - 1 & 2 & - 3 3 & - 2 & 1 2 & 1 & - 3 \end{matrix} ∣ ∣ ∣ ∣$ is

A

4

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B

- 4

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C

18

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D

- 18

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Solution

The correct option is B $- 4$
Using 'Sarrus' method : $∣ ∣ ∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣ ∣ ∣ = [a_{1} b_{2} c_{3} + b_{1} c_{2} a_{3} + c_{1} a_{2} b_{3}] - [a_{3} b_{2} c_{1} + b_{3} c_{2} a_{1} + c_{3} a_{2} b_{1}] = [- 6 + 4 + (- 9)] - [(- 18) + (- 1) + 12] = - 4$

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