The value of -116-a0 - -116a-0 - 64-12 - -32-45 is-

The correct option is C 78 ( 1 16 #160; ) a ^ 0 +( 1 16a #160; ) #160; ^ 0 64 ^ 1 2 #160; ( 32) ^ 4 5 #160; = 1 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Relations

The value of ...

Question

The value of $[\frac{1}{16}] a^{0} + [\frac{1}{16 a}]^{0} - 64^{\frac{- 1}{2}} - (- 32)^{\frac{- 4}{5}}$ is:

1 \frac{13}{16}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 \frac{3}{16}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{7}{8}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{16}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

$\frac{1}{1 \times 4} + \frac{1}{4 \times 7} + \frac{1}{7 \times 10} + \frac{1}{10 \times 13} + \frac{1}{13 \times 16} + \frac{1}{16 \times 19}$ =

D_{k} = ∣ ∣ ∣ ∣ ∣ \begin{matrix} a & 2^{k} & 2^{16} - 1 b & 3 (4^{k}) & 2 (4^{16} - 1) c & 7 (8^{k}) & 4 (8^{16} - 1) \end{matrix} ∣ ∣ ∣ ∣ ∣

16 \sum k = 1 D_{k}

The rational number which is not lying between $\frac{5}{16}$ and $\frac{1}{2}$ is
$(a) \frac{3}{8}$

$(b) \frac{7}{16}$

$(c) \frac{1}{4}$

$(d) \frac{13}{32}$

Simplify: $[{(\frac{- 8}{16})}^{- 1} \times {(\frac{- 16}{5})}^{- 1}] \div {(\frac{16}{5})}^{- 1}$

2^{\frac{1}{4}} {.4}^{\frac{1}{8}} {.8}^{\frac{1}{16}} {.16}^{\frac{1}{32}} . . . . \infty

Join BYJU'S Learning Program