The value of 2x-44x-20-x2-25x2-7x-10- where x- 5 is

The correct option is D 12 The value of 2x 4 4x+20 × x ^ 2 25 x ^ 2 7x+10 = 2(x 2) 4(x+5) × (x 5)(x+5) (x 2)(x 5) = 2 4 = 1 2 ...

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Question

The value of $\frac{2 x - 4}{4 x + 20} \cdot \frac{x^{2} - 25}{x^{2} - 7 x + 10}$ , where $(x \neq 5)$ is

\frac{1}{4}

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\frac{1}{2}

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\frac{2}{x - 5}

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\frac{2}{x + 3}

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\int \frac{4 x^{5} - 7 x^{4} + 8 x^{3} - 2 x^{2} + 4 x - 7}{x^{2} (x^{2} + 1)^{2}} d x

Statement 1: The value of the polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ at x = -1 is 14.

Statement 2: The polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ when divided by x + 1, gives 14 as remainder.

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} - 2 x + 3 & 7 x + 2 & x + 4 2 x + 7 & x^{2} - x + 2 & 3 x 3 & 2 x - 1 & x^{2} - 4 x + 7 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x^{6} + b x^{5} + c x^{4} + d x^{3} + e x^{2} + f x + g

g

\frac{x^{2} - 7 x + 10}{x^{2} - 5 x - 14} \times \frac{x^{3} + 8}{x^{3} - 8} \times \frac{x^{2} + 2 x + 4}{x^{2} - 2 x + 4} \times \frac{x - 7}{x - 5} = ?

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