The value of cos11-sin11-cos11-sin11- is-

The correct option is B tan 56^∘ →cos11+sin11 cos11 sin11 = 1+tan11 1 tan11 =tan( 45+11 ) =tan( 56 ) ...

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Standard XII

Mathematics

Trigonometric Ratios of Multiples of an Angle

The value of ...

Question

The value of $\frac{(cos 11^{\circ} + sin 11^{\circ})}{(cos 11^{\circ} - sin 11^{\circ})}$ is:

- tan 304^{\circ}

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tan 56^{\circ}

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cot 214^{\circ}

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cot 34^{\circ}

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Solution

The correct option is B $tan 56^{\circ}$
$\to \frac{cos 11 + sin 11}{cos 11 - sin 11} = \frac{1 + tan 11}{1 - tan 11} = tan (45 + 11) = tan (56)$

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Similar questions

Q. Prove that

\frac{cos 11^{\circ} + sin 11}{cos 11^{\circ} - sin 11^{\circ}} = tan 56^{\circ}

Q. The value of

\frac{(cos 11^{\circ} + sin 11^{\circ})}{(cos 11^{\circ} - sin 11^{\circ})}

Q. Prove that
(i)

\frac{\cos 11 ° + \sin 11 °}{\cos 11 ° - \sin 11 °} = \tan 56 °

.

(ii)

\frac{\cos 9 ° + \sin 9 °}{\cos 9 ° - \sin 9 °} = \tan 54 °

(ii)

\frac{\cos 8 ° - \sin 8 °}{\cos 8 ° + \sin 8 °} = \tan 37 °

Prove that:
(i) $\frac{c o s 11^{\circ} + s i n 11^{\circ}}{c o s 11^{\circ} - s i n 11^{\circ}} = t a n 56^{\circ}$
(ii) $\frac{c o s 9^{\circ} + s i n 9^{\circ}}{c o s 9^{\circ} - s i n 9^{\circ}} = t a n 54^{\circ}$
(iii) $\frac{c o s 8^{\circ} - s i n 8^{\circ}}{c o s 8^{\circ} + s i n 8^{\circ}} = t a n 37^{\circ}$

sin 79^{\circ} cos 11^{\circ} + cos 79^{\circ} sin 11^{\circ} =

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The value of (cos11∘+sin11∘)(cos11∘−sin11∘) is:

The correct option is B tan56∘→cos11+sin11cos11−sin11=1+tan111−tan11=tan(45+11)=tan(56)

The value of $\frac{(cos 11^{\circ} + sin 11^{\circ})}{(cos 11^{\circ} - sin 11^{\circ})}$ is:

The correct option is B $tan 56^{\circ}$
$\to \frac{cos 11 + sin 11}{cos 11 - sin 11} = \frac{1 + tan 11}{1 - tan 11} = tan (45 + 11) = tan (56)$