The value of cot -cosec -1cot -cosec -1 is

The correct option is A 1+cos θsin θ nbsp; cotθ +cosecθ 1 / cotθ cosecθ +1 = (cotθ +cosecθ ) (cose c ^ 2 θ co t ^ 2 θ ) / cotθ cosecθ +1 ...

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General Solution of Trigonometric Equation

The value of ...

Question

The value of $\frac{c o t θ + c o s e c θ - 1}{c o t θ - c o s e c θ + 1}$ is

\frac{1 + c o s θ}{s i n θ}

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\frac{1 + s i n θ}{s i n θ}

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\frac{1 - c o s θ}{s i n θ}

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\frac{1 - s i n θ}{s i n θ}

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Similar questions

\frac{c o s θ - s i n θ + 1}{c o s θ + s i n θ - 1} = c o s e c θ + c o t θ

\frac{1}{c o s e c θ + c o t θ}

\frac{1}{sin θ}

\frac{1}{sin θ}

\frac{1}{c o s e c θ - c o t θ}

Prove the following trigonometric identities.
(i) $\frac{1 + cos θ + sin θ}{1 + cos θ - sin θ} = \frac{1 + sin θ}{cos θ}$

(ii) $\frac{sin θ - cos θ + 1}{sin θ + cos θ - 1} = \frac{1}{sec θ - tan θ}$

(iii) $\frac{cos θ - sin θ + 1}{cos θ + sin θ - 1} = cosec θ + cot θ$

(iv) $(sin θ + cos θ) (tan θ + cot θ) = sec θ + cosec θ$

(sec θ - cos θ)^{2} + (c o s e c θ - sin θ)^{2} - (cot θ - tan θ)^{2} =

cosec θ [\frac{1 - cos θ}{sin θ} + \frac{sin θ}{1 - cos θ}] - 2 {cot}^{2} θ

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