Question

The value of $\frac{{\left(0.96\right)}^3-{\left(0.1\right)}^3}{{\left(0.96\right)}^2+0.096+{\left(0.1\right)}^2}$ is:

• A. $0.86$
• B. $0.95$
• C. $0.97$
• D. $1.06$

Answer 1

The correct option is A $0.86$

Given expression $=\frac{{\left(0.96\right)}^3-{\left(0.1\right)}^3}{{\left(0.96\right)}^2+(0.96\times 0.1)+{\left(0.1\right)}^2}$
$=\left(\frac{a^3-b^3}{a^2+ab+b^2}\right)$
$=(a-b)$
$=(0.96-0.1)$
$=0.86$